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Rubab from Lahore uploaded 671 mcqs.
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zainab from Sargodha uploaded 406 mcqs.
Abdullah Sufyan from sargodha uploaded 351 mcqs.

Total MCQs=(2465)

Note: Some MCQs have already been deleted. All the irrelevant and below standard MCQs will be deleted later.

MCQ Number= 2042

Dated: Sun 03-Nov-19       Subject:Physics (XII) Rheostat can be functioned as

(A):  Variable resistor

(B):  Potential divider

(C):  Both a and b

(D):  Emf

Answer:C

MCQ Number= 1693

Dated: Sun 18-Aug-19       Subject:Chemistry (BA/BSc) For making of glass mirror one of the main solution used is that of ...

(A):  Iron

(B): Chromium

(C): Silver

(D): Mercury

Answer:C

MCQ Number= 2406

Dated: Wed 09-Sep-20       Subject:General Science (VII) A variegated leaf has no _________ in the white part.

(A): Chloroplasts

(B): Glucose

(C): Oxygen

(D): Chlorophyll

Answer:D

MCQ Number= 1886

Dated: Sun 27-Oct-19       Subject:Chemistry (XII) the common fullerene is

(A):  C20

(B):  C60

(C):  C74

(D):  C80

Answer:B

MCQ Number= 1753

Dated: Tue 20-Aug-19       Subject:Chemistry (XII) Its major constituents are hydroge (50%) methane (35%) carbon monoxide (8%) ....

(A):  Coke

(B): Coal gas

(C): Coal tar

(D): None

Answer:B

MCQ Number= 437

Dated: Sun 14-Jul-19       Subject:Maths (X) Roots of the equation 4x2 – 4x + 1 are

(A):  Real, equal

(B):  Real, unequal

(C):  imaginary

(D):  Irrational

Answer:A

MCQ Number= 718

Dated: Sun 28-Jul-19       Subject:Science (VIII) A child percentage can be determined by:

(A):  Gene testing

(B):  Gene therapy

(C):  Hybridization

(D):  Cloning

Answer:A

MCQ Number= 1542

Dated: Sat 17-Aug-19       Subject:Chemistry (XII) A state function is....

(A):  Microscopic property

(B): Macroscopic property

(C): Unique property

(D): Both A and C

Answer:B

MCQ Number= 178

Dated: Thu 11-Jul-19       Subject:Computer (X) ______________ is available in insert menu.

(A): FONT

(B): DROP CAP

(C): Hyperlink

(D): None

Answer:C

MCQ Number= 1120

Dated: Wed 14-Aug-19       Subject:Maths (VIII) 16. If E = set of even numbers and O= set of add numbers then E ∩ O will be:

(A): N

(B):  E

(C):  O

(D):  { }

Answer:D